Optimal. Leaf size=152 \[ \frac{5 a^2 (6 A b-7 a B) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{16 b^{9/2}}-\frac{5 a x \sqrt{a+b x^2} (6 A b-7 a B)}{16 b^4}+\frac{5 x^3 \sqrt{a+b x^2} (6 A b-7 a B)}{24 b^3}-\frac{x^5 (6 A b-7 a B)}{6 b^2 \sqrt{a+b x^2}}+\frac{B x^7}{6 b \sqrt{a+b x^2}} \]
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Rubi [A] time = 0.217056, antiderivative size = 152, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.227 \[ \frac{5 a^2 (6 A b-7 a B) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{16 b^{9/2}}-\frac{5 a x \sqrt{a+b x^2} (6 A b-7 a B)}{16 b^4}+\frac{5 x^3 \sqrt{a+b x^2} (6 A b-7 a B)}{24 b^3}-\frac{x^5 (6 A b-7 a B)}{6 b^2 \sqrt{a+b x^2}}+\frac{B x^7}{6 b \sqrt{a+b x^2}} \]
Antiderivative was successfully verified.
[In] Int[(x^6*(A + B*x^2))/(a + b*x^2)^(3/2),x]
[Out]
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Rubi in Sympy [A] time = 23.2889, size = 148, normalized size = 0.97 \[ \frac{B x^{7}}{6 b \sqrt{a + b x^{2}}} + \frac{5 a^{2} \left (6 A b - 7 B a\right ) \operatorname{atanh}{\left (\frac{\sqrt{b} x}{\sqrt{a + b x^{2}}} \right )}}{16 b^{\frac{9}{2}}} - \frac{5 a x \sqrt{a + b x^{2}} \left (6 A b - 7 B a\right )}{16 b^{4}} - \frac{x^{5} \left (6 A b - 7 B a\right )}{6 b^{2} \sqrt{a + b x^{2}}} + \frac{5 x^{3} \sqrt{a + b x^{2}} \left (6 A b - 7 B a\right )}{24 b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**6*(B*x**2+A)/(b*x**2+a)**(3/2),x)
[Out]
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Mathematica [A] time = 0.216914, size = 123, normalized size = 0.81 \[ \frac{5 a^2 (6 A b-7 a B) \log \left (\sqrt{b} \sqrt{a+b x^2}+b x\right )}{16 b^{9/2}}+\frac{x \left (105 a^3 B+a^2 \left (35 b B x^2-90 A b\right )-2 a b^2 x^2 \left (15 A+7 B x^2\right )+4 b^3 x^4 \left (3 A+2 B x^2\right )\right )}{48 b^4 \sqrt{a+b x^2}} \]
Antiderivative was successfully verified.
[In] Integrate[(x^6*(A + B*x^2))/(a + b*x^2)^(3/2),x]
[Out]
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Maple [A] time = 0.011, size = 185, normalized size = 1.2 \[{\frac{A{x}^{5}}{4\,b}{\frac{1}{\sqrt{b{x}^{2}+a}}}}-{\frac{5\,aA{x}^{3}}{8\,{b}^{2}}{\frac{1}{\sqrt{b{x}^{2}+a}}}}-{\frac{15\,{a}^{2}Ax}{8\,{b}^{3}}{\frac{1}{\sqrt{b{x}^{2}+a}}}}+{\frac{15\,A{a}^{2}}{8}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){b}^{-{\frac{7}{2}}}}+{\frac{{x}^{7}B}{6\,b}{\frac{1}{\sqrt{b{x}^{2}+a}}}}-{\frac{7\,Ba{x}^{5}}{24\,{b}^{2}}{\frac{1}{\sqrt{b{x}^{2}+a}}}}+{\frac{35\,{a}^{2}B{x}^{3}}{48\,{b}^{3}}{\frac{1}{\sqrt{b{x}^{2}+a}}}}+{\frac{35\,B{a}^{3}x}{16\,{b}^{4}}{\frac{1}{\sqrt{b{x}^{2}+a}}}}-{\frac{35\,B{a}^{3}}{16}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){b}^{-{\frac{9}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^6*(B*x^2+A)/(b*x^2+a)^(3/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*x^6/(b*x^2 + a)^(3/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.277213, size = 1, normalized size = 0.01 \[ \left [\frac{2 \,{\left (8 \, B b^{3} x^{7} - 2 \,{\left (7 \, B a b^{2} - 6 \, A b^{3}\right )} x^{5} + 5 \,{\left (7 \, B a^{2} b - 6 \, A a b^{2}\right )} x^{3} + 15 \,{\left (7 \, B a^{3} - 6 \, A a^{2} b\right )} x\right )} \sqrt{b x^{2} + a} \sqrt{b} - 15 \,{\left (7 \, B a^{4} - 6 \, A a^{3} b +{\left (7 \, B a^{3} b - 6 \, A a^{2} b^{2}\right )} x^{2}\right )} \log \left (-2 \, \sqrt{b x^{2} + a} b x -{\left (2 \, b x^{2} + a\right )} \sqrt{b}\right )}{96 \,{\left (b^{5} x^{2} + a b^{4}\right )} \sqrt{b}}, \frac{{\left (8 \, B b^{3} x^{7} - 2 \,{\left (7 \, B a b^{2} - 6 \, A b^{3}\right )} x^{5} + 5 \,{\left (7 \, B a^{2} b - 6 \, A a b^{2}\right )} x^{3} + 15 \,{\left (7 \, B a^{3} - 6 \, A a^{2} b\right )} x\right )} \sqrt{b x^{2} + a} \sqrt{-b} - 15 \,{\left (7 \, B a^{4} - 6 \, A a^{3} b +{\left (7 \, B a^{3} b - 6 \, A a^{2} b^{2}\right )} x^{2}\right )} \arctan \left (\frac{\sqrt{-b} x}{\sqrt{b x^{2} + a}}\right )}{48 \,{\left (b^{5} x^{2} + a b^{4}\right )} \sqrt{-b}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*x^6/(b*x^2 + a)^(3/2),x, algorithm="fricas")
[Out]
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Sympy [A] time = 61.5541, size = 233, normalized size = 1.53 \[ A \left (- \frac{15 a^{\frac{3}{2}} x}{8 b^{3} \sqrt{1 + \frac{b x^{2}}{a}}} - \frac{5 \sqrt{a} x^{3}}{8 b^{2} \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{15 a^{2} \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{8 b^{\frac{7}{2}}} + \frac{x^{5}}{4 \sqrt{a} b \sqrt{1 + \frac{b x^{2}}{a}}}\right ) + B \left (\frac{35 a^{\frac{5}{2}} x}{16 b^{4} \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{35 a^{\frac{3}{2}} x^{3}}{48 b^{3} \sqrt{1 + \frac{b x^{2}}{a}}} - \frac{7 \sqrt{a} x^{5}}{24 b^{2} \sqrt{1 + \frac{b x^{2}}{a}}} - \frac{35 a^{3} \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{16 b^{\frac{9}{2}}} + \frac{x^{7}}{6 \sqrt{a} b \sqrt{1 + \frac{b x^{2}}{a}}}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**6*(B*x**2+A)/(b*x**2+a)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.238776, size = 184, normalized size = 1.21 \[ \frac{{\left ({\left (2 \,{\left (\frac{4 \, B x^{2}}{b} - \frac{7 \, B a b^{5} - 6 \, A b^{6}}{b^{7}}\right )} x^{2} + \frac{5 \,{\left (7 \, B a^{2} b^{4} - 6 \, A a b^{5}\right )}}{b^{7}}\right )} x^{2} + \frac{15 \,{\left (7 \, B a^{3} b^{3} - 6 \, A a^{2} b^{4}\right )}}{b^{7}}\right )} x}{48 \, \sqrt{b x^{2} + a}} + \frac{5 \,{\left (7 \, B a^{3} - 6 \, A a^{2} b\right )}{\rm ln}\left ({\left | -\sqrt{b} x + \sqrt{b x^{2} + a} \right |}\right )}{16 \, b^{\frac{9}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*x^6/(b*x^2 + a)^(3/2),x, algorithm="giac")
[Out]